Question

Two metallic oxides contain 27.6% and 30% oxygen respectively. If the formula of the first oxide is X3O4, that of the second will be?

Answer 1

Hi friend,

At frist thanks for the question!!

Given that formula of the first oxide = M304

Let mass of the metal = X

% of metal in M3O4 = ( 3x/3x+64 )*100

but as give % age = ( 100- 27.6 ) = 72.4 %

so, ( 3x / 3x+ 64 ) * 100 = 72.4 %

or X = 56.

in 2nd oxide ,

oxigen = 30 % .....so metal = 70 %

so, the ratio is :-

M : O
70/56 : 30/16
1.25 : 1.875
2 : 3

so, 2nd oxide is M2O3

.....i hope it helps you.

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