Two metallic spheres of radii r and 2r are charged so that both of these have same surface charge density σ . if they are connected to each other with a conducting wire, in which direction will the charge flow and why?
Answers
Answered by
65
Given that the radius of smaller sphere is R and that of larger sphere is 2R and their common surface charge density is ρ. So initial charge will be less in smaller sphere and more in larger sphere. After they are connected by a thin conducting wire remaining at a large distance apart their charge will be redistributed until they gain same potential. Let this explain by below..
Potential on and inside of charged sphere is given by,
V=1/4pieE0*q/r
= 1/4pieE0*4pier squared O/r
Therefore V directly proportional to r
That is, the sphere having larger radius will be at a higher potential.
Therefore, charge will flow from bigger sphere to smaller sphere.
Potential on and inside of charged sphere is given by,
V=1/4pieE0*q/r
= 1/4pieE0*4pier squared O/r
Therefore V directly proportional to r
That is, the sphere having larger radius will be at a higher potential.
Therefore, charge will flow from bigger sphere to smaller sphere.
Answered by
8
Answer:
I hope its helpfulll.....
Explanation:
Attachments:
Similar questions