Question

two metallic wires A and B are connected in parallel. Wire A has length L and radius R wire B has length 2L and radius 2r. Compute the ratio of the total resistance of parallel combination and resistance of wire A.
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Answer 1

Answer:

The ratio of \bold{R_{p} \text { and } R_{A} \text { is } 1 : 3}

Explanation:

Given:

Wire A:  

Length = l  

Radius = r

Wire B;

Length = 2l

Radius = 2r  

Resistance of A : R_{A}=\frac{\rho \times l}{\pi r^{2}}

Resistance of B : R_{B}=\frac{\rho \times 2 l}{\pi\left(2 r^{2}\right) \times 2}    

The resistance R_{p} for the parallel combination must be written as:

1/rp=1/Ra+1/Rb

Hence the ratio of R_{p} \text { and } R_{A} will be 1 : 3.

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Answer 2

Answer:

jsksowooqooqlll

sorry but IDK the answer