Question

Two metallic wires A and B are connected in series .The wire A has length l and radius R, while wire B has length 2L and radius 2r . find the ratio of total resistance of series combination and the resistance of wire A , if both the wires of the same material .​

Answer 1

Answer:

Answer is B.

Now when the resistance are connected in seires is R=RA+RB R = R A + R B . That is, R=32(qlπr2) R = 3 2 ( q l π r 2 ) . So, the required ratio is R:RA=32(qlπr2):qlπr2 R : R A = 3 2 ( q l π r 2 ) : q l π r 2 .

Explanation:

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Answer 2

Here it's all well sis

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