Question

Two metallic wires having R1=5ohm and R2=50ohm are joined in parallel across a battery. What os the ratio of energy consumed by R1 and R2 in time t?​

Answer 1

Answer:

1:10

Explanation:

I =VR

Therefore, I 1 = 5V

I2 = 50V

we know that , Q = It

Q1= 5Vt

Q2= 50Vt

$voltage = \frac{energy}{charge } \\ voltage \times charge = energy$

$energy \: by \: r1 = 5 {v}^{2} t \\ energy \: by \: r2 = 50 {v}^{2} t \\ \\ \frac{energy \: by \: r1}{energy \: by \: r2} = \frac{5 {v}^{2 } t}{50 {v}^{2}t } = \frac{5}{50} = \frac{1}{10}$

therefore, E1:E2 : : 1:10 is the ratio