two mettalic wires having resistance r1=5ohm&r2=10ohm are joined in parallel across a battery. what will be the ratio of energy consumed by the r1 &r2 in time t.?
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Two wires having resistances 5Ω and 10Ω are connected in parallel across a battery.
We have to find ratio of energy consumed by the R₁ and R₂
Remember that, Potential difference across each resistor in parallel connection remains same.
Let voltage of battery be V.
Therefore voltage across R₁ and across R₂ will also be V.
Energy consumed by resistor in parallel connection is given by
- E = V²/R
★ Energy consumed by R₁ :
➝ E₁ = V²/R₁
➝ E₁ = V²/5 ___ (I)
★ Energy consumed by R₂ :
➝ E₂ = V²/R₂
➝ E₂ = V²/10 ___ (II)
By taking ratio of (I) and (II), we get
➝ E₁/E₂ = V²/5 × 10/V²
➝ E₁/E₂ = 10/5
➝ E₁ : E₂ = 2 : 1
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