two mixtures equal quantity contain wine,water ,alcohol in the ratio of 6:5:3 &3:5:6 respectivly ,from the mixture 20% of wine &25 % of water &40% of alcohol is taken out for the seond container too,then waht is new ratio?
Answers
Given : two mixtures equal quantity contain wine,water ,alcohol in the ratio of 6:5:3 &3:5:6 respectively ,from the mixture 20% of wine &25 % of water &40% of alcohol is taken out from both containers
To find : new ratio of Mixtures
Solution:
two mixtures equal quantity contain wine,water ,alcohol in the ratio of 6:5:3 &3:5:6
Let say Wine in mixture 1 = 6 A
Water in mixture 1= 5A
Alcohol in Maxture 1 = 3A
Total = 6A + 5A + 3A = 14A
in Maxture 2
Wine = 3A
Water = 5A
Alcohol = 6A
20% of wine &25 % of water &40% of alcohol is taken out
Mixture 1 :
Remaining wine = 6A -(20/100)6A = 4.8A
Remaining water = 5A -(25/100)5A = 3.75A
Remaining Alcohol = 3A -(40/100)3A = 1.8A
Ratio 4.8 : 3.75 : 1.8
=> 480 : 375 : 180
=> 32 : 25 : 12
Mixture 3 :
Remaining wine = 3A -(20/100)3A = 2.4A
Remaining water = 5A -(25/100)5A = 3.75A
Remaining Alcohol = 6A -(40/100)6A = 3.6A
2.4 : 3.75 : 3.6
=> 240 : 375 : 360
=> 16 : 25 : 24
Ratio of new mixture : 32 : 25 : 12 & 16 : 25 : 24
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