Chemistry, asked by armaangarg447, 11 months ago

Two mole of a monoatomic ideal gas is expanded
irreversibly and isothermally at T Kelvin until its volume
is doubled and q joules heat is absorbed from surrounding.
S (J/K) (system + surrounding) is :
(a) zero
(b) 2 Rln2–q/T
(C) 3Rln2–q/T
(d)-2 Rln2+q/T​

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Answers

Answered by antiochus
0

Answer:

Given that n=2

T=T Kelvin

V_{1} =V  and V_{2} =2V

q=q joules

ΔS_{surr}= \frac{-q}{T}

ΔS_{sys} =C_{V} ln\frac{T_{2} }{T_{1} } +R ln \frac{V_{2} }{V_{1} }

dq=dV+pdV

dq=nC_{V} dT+\frac{nRT}{V} dV

dS=\frac{dq}{T}

dS=\frac{nC_{V} dT}{T} +\frac{nRdV}{V}

ΔS=nC_{V} \int\limits^T_T _\frac{dT}{T}+nR\int\limits^V_V\frac{dv}{v}

ΔS=nC_{V} ln\frac{T_{2} }{T_{1} } +nRln\frac{V_{2} }{V_{1} }

Here finally we got

ΔS_{sys} =nRln\frac{V_{2} }{V_{1} }

so we get ΔS(system+surrounding)=

                                 2Rln2-q/T

option b is correct

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