Question

Two mole of an ideal gas is kept at 27°C.It is compressed to 1/4th of its initial volume. Calculate the heat released in this process if the temperature remains constant. R=8.314J/mol/K​

Answer 1

Answer:

Explanation:

q=u+w

here as it is isothermal process, q=w

work done in isothermal process=2.303*nrt*log(v2/v1)

                                                       =2.303*2*8.314*300*log(1/4)

                                                       =11488.2852*(-log4)

                                                        = -6916.63J

so heat release is 6916.63 joules