Question

Two mole of n2h4 release 16mole of electron .Then convert into new compound .Then oxidation no. Of nitrogen in the new compound are?

Answer 1

Oxidation state of NItrogen in n2h4 is -2. 2(-2) + 4(+1)= 0

therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .

then ox state of N is +3 in the new compound Y.

Answer 2

$\huge\underline\mathfrak\purple{Answer}$

Oxidation state of NItrogen in n2h4 is -2. 2(-2) + 4(+1)= 0

therefore two N makes it -4 , since they lose 10 e- , hence total charge is +6, and since H is still +1 , Two N divides the +6 .

then ox state of N is +3 in the new compound Y.

$\huge\underline\mathfrak\purple{Thanks}$