Two molecules of solid mercury(II) oxide decomposes to form two molecules of liquid mercury and one molecule of oxygen gas. What amount of oxygen is produced from the decomposition of 4.0 mol of mercury(II) oxide?
options:
a) 4.0 mol
b) 1.0 mol
c) 8.0 mol
d) 2.0 mol
Answers
Answer:
2.0 moles of Oxygen should be use
Answer:
Brainly.in
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Secondary School Math 5 points
If alpha and beta are the zeroes of x2-x-4 find out the value of
1) 1/alpha + 1/beta - alpha beta
2) alpha/beta + beta/alpha +2 ( 1/alpha +1/beta) + 3*alpha*beta..
plzz its urgent......
Ask for details Follow Report by Arohi03 06.05.2018
Answers
THE BRAINLIEST ANSWER!
Sol : We have quadratic equation x² - x - 4.
Given α and ß are their zeroes.
We know that,
Sum of roots = - ( coefficient of x )/ coefficient of x²
α + ß = - ( - 1 ) / 1
α + ß = 1 / 1 = 1.
Now,
Product of roots = constant term / coefficient of x²
αß = ( - 4 ) / 1
αß = -4.
1. 1/α + 1/ß - αß
ß + α
= ------------- - αß
αß
By substituting the values of ( α + ß ) and ( αß ),
= ( 1 / -4 ) - ( - 4 )
= ( - 1 / 4 ) + 4
- 1 + 16
= ----------------
4
= 15 / 4.
2. α/ß + ß/α + 2 ( 1/α + 1/ß ) + 3αß
α² + ß² + 2ß + 2α
= --------------------------- + 3αß
αß
α² + ß² + 2 ( α+ß )
= ------------------------- + 3αß ----- eq.1
αß
Now ,we don't have the value of ( α² + ß² ), so let's find it ,
( α + ß )² = α² + ß² + 2 αß
By substituting the values of ( α + ß ) and αß in above equation,
( 1 )² = α² + ß² + 2 ( - 4 )
1 = α² + ß² - 8
α² + ß² = 1 + 8
α² + ß² = 9
Now by substituting the values of ( α² + ß² ) ,αß and ( α + ß ) in eq.1,
9 + 2 ( 1 )
= --------------- + 3 ( - 4 )
-4
9 + 2
= -------------- - 12
-4
- 11
= -------------- - 12
4
-11 - 48
= --------------
4
= -59/4.