Question

Two moles of 02 (Y= at temperature T, and 3 moles
of CO2 Y= at temperature 2T, are allowed to mix
together in a closed adiabatic vessel. The resulting
mixture finally comes in thermal equilibrium. Then

Answer 1

Thus final temperature of the mixture is T = 23 To / 14

Explanation:

We are given that:

• γ for O2 = 7 / 5
• γ for CO2 = 4 / 3

Solution:

n1 Cv1 T1 + n2 Cv2 T2 = (n1 + n2) Cv T

3 ( 5R / 2 ) To + 3 x ( 3R) (2To) = 5 Cv(T)

Cv = n1 Cv1 + n2 Cv2 / n1 + n2

15 R To / 2 + 18R T o = ( 15 R / 2 + 9 R ) T

T = 23 To / 14

Thus final temperature of the mixture is T = 23 To / 14