Question

two moles of a monoatomic of a gas are mixed with 'n' moles of a polyatomic gas. if mixture behave like diatomic gas, then the value of 'n' is​

Answer 1

The value of 'n' is​ 1/2

Explanation:

Let the ratio of the polyatomic and monoatomic gas is given as:

⇒ n : 1

The mole transfer of the gas is given as:

Q₁ = n((f₁R)/2)ΔT

The mole transfer of another gas is given as:

Q₂ = 1 × ((f₃R)/2)ΔT

Now, the total mole transfer is given as:

Q = (n + 1)((f₂R)/2)ΔT

∵ Q = Q₁ + Q₂

(n + 1)((f₂R)/2)ΔT = (n((f₁R)/2)ΔT) + (n((f₃R)/2)ΔT)

(n + 1)f₂ = nf₁ + f₃

(n + 1)5 = n(3) + 6

5n + 5 = 3n + 6

5n - 3n = 6 - 5

2n = 1

∴ n = 1/2