Question

Two moles of ammonia is introduced in a evacuated
500 mL vessel at high temperature. The
decomposition reaction is:
2NH3(g) = N2(g) + 3H2(g)
At the equilibrium NH, becomes 1 mole then the K
Tould be​

Answer 1

Answer:

Answer:  for this reaction is 1.6875.

Explanation: We are given,

Volume of the vessel = 1L

For a reaction,

            

at t = 0      2            0         0

at      2-2x        x       3x

at t = t        0            x         3x

where, 2x = change in moles of

It is given that at equilibrium, amount of left is 1 mole,

Concentration can be calculated as

So, the concentraction of , and at equilibrium will be,

= 1.0 mol/L

= 0.5 mol/L

= 1.5 mol/L

For a given reaction, can be calculated as:

= 1.6875