Two moles of an ideal gas at 300 K were cooled at constant volume so that the pressure is reduced to half the initial value. Then as a result of heating at constant pressure the gas has expanded till it attains the original temperature. The total heat absorbed by gas, if Ris the gas constant А A 150R B 300R C 75R D 100R
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In isochoric process P∝T
If pressure halves, temperature halves.
Heat released during isochoric process=nC
V
(T
2
−T
1
)=2×(
2
3
R)(300−150)J=450RJ
Heat absorbed during isobaric expansion=nC
P
R(T
3
−T
2
)=2×(
2
5R
)(300−150)J=750RJ
Thus net heat absorbed=300RJ
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