Question

Two moles of an ideal gas is compressed isothermally and reversibly from a volume 2 L to 0.5 L at initial pressure of 1 atm The work done by gas​

Answer 1

Answer:

No. of moles of the ideal gas, n = 2

The volume of the gas is compressed isothermally and reversibly, so

V₁ = 2 L and V₂ = 0.5 L

Initial Pressure = 1 atm

We know,

The work done in isothermal process is given by,

W = - P ∆V = - P * (V₂ – V₁)

∴ W = - 1 atm * (0.5 - 2) L = 1.5 L atm = + 1.5 * 101.3 J L⁻¹ atm⁻¹ = + 151.95 J

[The positive sign of work done indicates that the work is done by the surrounding on the system.]

Hence, the work done by the gas is 151.95 Joules.