Question

Two moles of an ideal gas undergoes following
process as
A(T)
1.01
B
T=T,
P→ (atm)
0.5
-
C (T)
20 L
40 L
V(L)
Correct option(s) among the following is/are
(1) AU = AS = 0
(2) WBC = 0
(3) Wcycle + 0
(4) All of these​

Answer 1

Explanation:

AB-Isobaric process

BC-Isochoric process

CA-Isothermal process

Total work =w

AB

+w

BC

+w

CA

=−P×ΔV+2.303nRTlog(

V

1

V

2

)

=−1×20×101.3+0+2.303×2×8.314×Tlog

20

40

...(i)

PV=nRT (At A)

1×20=2×0.0821×T

T=121.8K

From eq.(i)

Total work=−2026+2.303×2×8.314×121.8log2=−622.06J

In cyclic process:

ΔU=0,ΔH=0,ΔS=0