Question

two moles of each reactant A and B are taken in a reaction flask the react in the following manner
A(g) +B(g)gives C(g) + D(g)
at equilibrium it was found that the concentration it was found that the concentration of C is triple that of B the equilibrium constant for the reaction is

Answer 1

Hey dear,

● Answer - 9

● Explaination-
Let's see the reaction.
Reaction A + B ---> C + D
Initial 2 2 0 0
Equibrium 2-x 2-x x x

But we know, at equilibrium
[C] = 3[B]
x = 3(2-x)
x = 1.5

Therefore,
[A] = 2-x = 0.5
[B] = 2-x = 0.5
[C] = x = 1.5
[D] = x = 1.5

Equilibrium costanct is,
Kc = [C][D] / [A][B]
Kc = (1.5×1.5) / (0.5×0.5)
Kc = 9

Hope this is helpful...

Answer 2

two moles of each reactant AandB are taken in a reaction flask and react in the following manner A(g) + B (g) gives C(g) +D(g) at equilibri it was found that the concentration of C is triple that of B the equilibrium constant for the reaction is -9