Question

Two moles of hydrogen and 0.3 moles of oxygen are reacted with each other to form liquid water.Volume of the contentents remained in the container in liters after the completion of the reaction at “I” bar pressure and 273K is ”X”.The value x/3.531 is​

Answer 1

3.531*273k= 776minimum

Answer 2

Answer:

given = 2 moles of hydrogen

          0.3 moles of oxygen

         P = I bar.

         T  =  273k

to find = X/ 3.531

solution =

2H₂ + O₂  ----------⇒ 2H₂O

no.of moles of hydrogen = 2moles

no.of moles of oxygen =2 moles ,

so, 1 mole of O₂ is left

so, H₂ is completed in the reaction

so, H₂ is limiting reagent .

3.531 × 273 = 776 minimum.

the correct answer is 776 .

the value of X is 776