two moles of ideal gas is expanded reversibly from 4atm. to 3 atm at const temperature of 300k calculate work done ( ans -332)
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Dear Student,
◆ Answer -
W = -1435 J
● Explanation -
# Given -
n = 2 mol
P1 = 4 atm
P2 = 3 atm
T = 300 K
# Solution -
Work done is calculated as -
W = -2.303nRT.log(P1/P2)
W = -2.303 × 2 × 8.314 × 300 × log(4/3)
W = -11488 × 0.1249
W = -1435 J
Therefore, -1435 J of work is done during process.
Thanks dear...
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