Two moles of n2 and two moles of h2 are placed in a closed vessel of 5 litre caacity and suitable conditions are rovided for yhe reaction .When the equilibrium is reached it is found that a half mole of n2 is used up find equilibrium concentration of nh3
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N2 + 3H2 ----> 2NH3
Initial moles 2 2 0
Equilibrium moles 2- 2-3 2
Since 0.5 mole of N2 has been used up therefore :
= 0.5 mole
Moles of NH3 = 1
Concentration of NH3 = moles/volume = 1/5 mol/l
Initial moles 2 2 0
Equilibrium moles 2- 2-3 2
Since 0.5 mole of N2 has been used up therefore :
= 0.5 mole
Moles of NH3 = 1
Concentration of NH3 = moles/volume = 1/5 mol/l
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