Question

Two moles of oxygen contained in vessel A and two moles of oxygen contained in vessel B. both vessels have equal volume and temperature. pressure in which of these bottles is higher.

Answer 1

Answer:

Pressure remains same in both

Answer 2

Answer:-

Both pressures are equal

Explanation:-

Given:-

• $n_A = n_B = 2$
• $T_A = T_B$
• $V_A = V_A$

To Find:-

Ratio of pressures

Solution:-

Using, Ideal gas equation

PV = nRT

$P_AV_A = n_ART_A \: -----(1)$

$P_BV_B = n_B R T_B \: -----(2)$

(1)÷ (2)

$\dfrac{P_AV_A}{P_BV_B} =\dfrac{ n_ART_A}{n_B R T_B}$

$\dfrac{P_A \cancel{V_A}}{P_B\cancel{V_A}} =\dfrac{\cancel{ n_ART_A}}{\cancel{n_A R T_A}}$

$\dfrac{P_A}{P_B} =\dfrac{ 1}{1}$

$\therefore P_A = P_B$