Question

Two moles of pcl5 were heated in closed vessel of 2 litre capacity, at equilibrium 40% of pcl5 was dissociated into pcl3 and cl2. The value of equilibrium constant is

Answer 1

Hi, please consider the answer given below;

When two moles PCl5 were heated in closed vessel of 2 litre capacity, at equilibrium 40% of PCl5 was dissociated into PCl3 and Cl2. The value of equilibrium constant is calculated as follows;

The equation for dissociation of PCl5 is

the initial concentration of PCl5 is 2/2 = 1 M

                  PCl5 ------------> PCl3 + Cl2

initial              1                         0         0

at equilibrium  0.6                   0.4      0.4

The equillibrium constant is = [PCl3][Cl2]/[PCl5]

                                                = 0.4 x 0.4/0.6

                                                 = 0.27

Answer 2

Answer:

0.266

Explanation:

Hope this will help u