Question

Two moles of pcl5 were heated to 327oc in a closed two litre vessel and when equilibrium was achieved, pcl5 was found to be 40% dissociated into pcl3 and cl2. Calculate the equilibrium constant (kc) for the reaction.

Answer 1

Explanation:

PCl

5

⇌PCl

3

+Cl

2

2moles − −

2(1−α) 2α 2α α=40% =0.4

V=2lit

[PCl

5

]=

V

2(1−α)

=

2

2(1−0.4)

=0.6mol/L

[PCl

3

]=[Cl

2

]=

2

2(0.4)

=0.4mol/L

K

C

=

0.6

0.4×0.4

=0.27molL

−1

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