Question

Two monatomic ideal gases 1 and 2 of molecular masses m₁ and m₂ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas 1 to that in gas 2 is given by(a) $\sqrt{\frac{m_{1}}{m_{2}}}$(b) $\sqrt{\frac{m_{2}}{m_{1}}}$(c) $\frac{m_{1}}{m_{2}}$(d) $\frac{m_{2}}{m_{1}}$

Answer 1

ur answer is option no c

Answer 2

Answer:

√m2/m1

Explanation:

Molecular mass of gas 1 = m1

Molecular mass of gas 2 = m2

Temperature of both the gases = T = Constant

Velocity of sound in a gas v

Therefore,

v1/v2 = √m2/m1 as R,T are constant factors

Thus, ratio of the speed of sound in gas 1 to that in gas 2 is given by √m2/m1