Two monobasic acids A and B are titrated separately aganist 1 N
Na2CO3 solution. 10ml of A requires 25 ml of Na2CO3 Solution,
whereas 40 ml of B requires 250ml of Na2CO3 solution.
What volume of A and B should be mixed together to
produce one litre of 1 N acid solution?
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Answer:
Explanation:
equivalent of a = 25
normality*v=25
normlity*10=25
normality = 25/10
equivalent of b = 250
normality*40=250
normality = 25/4
n1v1+n2v2 = 1
n1(1-v2)+n2v2 = 1
n1-n1v2+n2v2 = 1
v2(n2-n1) = 1-n1
v2 = 1-25/10 / 25/4 - 25 / 10
v2 = -15/10 / 15/4
v2 = 4/10=400 ml
v1 = 6/10 =600 ml
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