Question

Two monochromatic light waves of equal intensities produce an interference pattern at a point in the pattern, the phase difference between the interfereing waves is π/3 rad .Express the intensity at this point as a fraction of the maximum intensity in the pattern

Answer 1

Answer:

the intensity at this point as a fraction of the maximum intensity in the pattern is given as

$\frac{I}{I_{max}} = \frac{3}{4}$

Explanation:

As we know that the intensity of the two waves after superposition at a given point is given as

$I = I_{max} cos^2(\frac{\phi}{2})$

here we know that

$\phi = \frac{\pi}{3}$

now we know to find the ratio of intensity at the given point with maximum intensity

so we will have

$\frac{I}{I_{max}} = cos^2(\frac{\pi}{6})$

$\frac{I}{I_{max}} = \frac{3}{4}$

#Learn

Topic : Interference

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