Question

two motor car starting off with the time gap of 2 minute travel in the same direction with the same acceleration time taken by the second cars in its departure to complete one by 9th of the distance covered by the first car is

Answer 1

time taken by 2nd car to cover 1/9th distance travelled by first car in 2 min is 2/3min

Answer 2

Time taken by first car to travel 'x' distance when the velocity is 'v' m/s = x/v units

Time taken by second car to travel x/9 distance when the velocity is same=[(x/9)÷v]+2
= x/9v + 2
= (x + 18v)/9v seconds


hope it helps......