two motor mechanics Raju and Siraj working together can overhaul a scooter in 6 hours. Raju alone can do the job in 15 hours. In how many hours can siraj alone do it
Answers
Answered by
7
Answer:
Number of hours Raju required to overhaul a scooter : 15 hours
Let number of hours siraj required to overhaul a scooter : X hours
Number of hours required by Raju and Siraj together to do a piece of work : 6 hours
Work done by Raju in one hour:
Work done by Siraj in one hour:
Work done by Raju and Siraj together in a one hour :
Work done by Raju and Siraj together in one hour :
=
=
⇒ 6X +90 = 15X
⇒ 9X = 90
⇒ X =
= 10 hours
Answered by
6
Answer:10 days
Step-by-step explanation:
subtract the total work from the work done by raju alone
i.e
work done together=1/6 (hours)
work done by raju alone = 1/15 hours
work done by siraj = total work - work done by by raju
= 1/6 - 1/15
= 5 -2 /30
= 3/30
=1/10
=10 days
therefore siraj can complete the work alone in 10 days
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