Question

Two motorcycles are traveling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel?

Answer 1

Step-by-step explanation:

Hi Sofia

Here's your answer.

let the distance covered by the slower one be y km

distance covered by the faster one =2y km

the difference of their times is 4

So,

time taken by faster one-time taken by slower one=4

(distance covered by faster one/Speed of faster one)-(distance covered by the slower one/Speed of slower one)=4

2y/120-y/90=4

taking LCM

(2y×3-y×4)/360=4

6y-4y=4×360

2y=1440

y=1440/2

y=720

distance covered by slower one=720km

Hope, it helps.