Question

Two motorists met at 10
a.M. At the dadar railway station. After their meeting one of them proceeeded in the east direction while the other proceeded in the north direction. Exactly at noon, they were 60 km aprt. Find the speed of the slower motorist if the difference of their speeds is 6 km/hr.

Answer 1

T = 2hours

Distance between the drivers = 60Km

Speed of driver 1 = x km/h

speed of driver 2 = x+6 km/h

√(d1^2 + d2^2) = 60

find x

d = s×t

(2(x))^2 + (2(x+6))^2 = 60^2

4x^2 + (2x+12)^2 = 60^2

2x + 2x + 12 = 60

4x = 60-12

x = 48/4

= 12m/s

speed of slower motorist = 12m/s