two mubers are differed by .four and their product is 192 find the numers
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the number are 12,16 there product is 192
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One No. = x
Other No. = y
x - y = 4
x = y + 4 ........ Eq. 1
xy = 192
y = 192 / x ..... Eq 2
Sub y + 4 from Eq. 1 for x in Eq. 2:
y = 192 / (y + 4)
y(y + 4) = 192
y² + 4y = 192
y² + 4y - 192 = 0
(y - 12)(y + 16) = 0
If the product of two factors equals zero, then one or both factors equal zero.
If y - 12 = 0,
y = 12
and
x = 12 + 4
x = 16
If y + 16 = 0,
y = - 16
and
x = - 16 + 4
x = - 12
The two numbers are 12 & 16 or - 12 & - 16.
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