Question

Two musical instruments were purchased for rs 8000. the first was sold at a profit of 40% and second at a loss of 40%. if the sale price was same in both the cases , then the cost price of the cheaper instrument was?

Answer 1

Let X be the cost price of 1 instrument

Cost price of other instrument=8000-X

profit on 1st instrument=40%

Selling price=X(1+40/100)=1•4X

Loss on 2nd instrument=40%

Selling price=(8000-X)(1–40/100)=(8000-X)ו6=4800-•6X

Since selling price is same

1•4X=4800-•6X

1•4X+•6X=4800

X=2400 cost price of 1 instrument

8000–2400=5600 cost price of 2nd instrument

hence cost price of cheaper instrument was 2400

Answer 2

Given:

• Two musical instruments were purchased for rs 8000.
• The first was sold at a profit of 40%
• Second at a loss of 40%
• Sale price was same in both the cases

To find:

The cost price of the cheaper instrument

Solution:

Let the cost price for both instruments be x and y respectively.

Now,

x + y = 8000 ....(1)

Sale price for first instrument is

x + 40x/100...(2)

sale price for second instrument is

y - 40y/100 ...(3)

now, it is given that the selling price for both were equal

x + 40x/100 = y - 40y/100

140x = 60y

7x = 3y

7x/3 = y .. (4)

Putting value of y from 4 in 1

x + 7x/3 = 8000

10x = 24000

x = 2400

Putting the value of x in 4

7 (2400)/ 3 = y

5600 = y

Hence the cost price for the cheaper instrument was Rs. 5600.