Two mutually perpendicular forces of 8N and 6N acts on the same body of mass 10kg.Find (a) Net force acting on the body. (b) magnitude of acceleration of body.
Answers
Answer:
| 6N / F Let O be the body of 10 kg. Resultant force on the body , F=( 82 + 62) 1/2 = 10 N ( net force on the body)
| /
| / Magnitude of accn= F/m=10/10=1 ms-2
| / let the force F make an angle B with the horizontal. the accn will also make the angle B with the horizontal as accn is O--------------------------8N in the same direction of force.
tan B=6/8 => B=tan-13/4. (direction of accn)
Explanation:
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Answer:
The two mutually perpendicular forces of 8N and 6N acts on the same body of mass 10kg
Explanation:
(a) Net force acting on the body.
(b) magnitude of acceleration of body.