Question

Two natural number differ by 3 and
their product is 504 find the number​

Answer 1

Answer:

suppose that first number is => t

So, second number is => t+3

t(t+3) = 504

${t}^{2} + 3t - 504 = 0 \\ \\ {t}^{2} + 24t - 21t - 504 = 0 \\ \\ t(t + 24) - 21(t + 24) = 0 \\ \\ t = 21 \: \: \: \: and \: \: \: \: t = - 24$

So , Your number is 21 and 24

OR

Number is -24 , -21

Answer 2

let the numbers be x & x+3

x(x+3)=504

x²+3x=504

x²+3x-504=0

solving equation using -b±√b²-4ac/2a,

x= -3±√3²-4×1×-504/2

=-3±√9+2016/2

=(-3±53.89)/2

=50.89/2

=25.445

x+3= 27.445

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