Question

two natural number differ by 5 and their product is 36 . Find the number​

Answer 1

Answer: 9 and 4

Step-by-step explanation:

Let first no a then second is a-5

Now a.t.q.

(A)*(a-5)=36

A^2-5a-36=0 (solve this quadratic equation)

A^2-9a+4a-36=0

a(a-9)+4(a-9)=0

Taking factors..

(a-9) (a+4)

natural number cannot be negative so.

A=9

Therefore first no is 9 and second is 9-5= 4

Answer 2

Answer:

Hence your answer is 4,9

Hopes it is correct and helps you..;›