Question

two natural numbers are such that they differ by 2 and their product is 48 find the number​

Answer 1

Answer:

Let the numbers be a and b.

Given:

Difference of the numbers = 2

→ a - b = 2 -- equation (1)

Product of the numbers = 48

→ ab = 48 -- equation (2)

We know that,

(a + b)² = (a - b)² + 4ab

→ (a + b)² = (2)² + 4(48)

→ (a + b)² = 4 + 192

→ (a + b)² = 196

→ a + b = 14 -- equation (3).

Adding equations (1) & (3) we get,

→ 2a = 2 + 14

→ 2a = 16

→ a = 8

Substitute a in equation (1)

→ a - b = 2

→ 8 - b = 2

→ b = 8 - 2

→ b = 6

The numbers are 8 and 6 .

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