Question

two natural numbers are such that they differ by 2 and their product is 48 . Find the number​

Answer 1

Answer:

Let two numbers be x,y

x-y =2

x = 2+y

x(y) = 48

put value of x here

(2+y) (y) = 48

2y + y² = 48

y² + 2y - 48 = 0

y² + 8y - 6y - 48 = 0

y (y+8) - 6(y+8) = 0

(y-6) (y+8) = 0

y = 6, -8

6 is natural number so y = 6

x = 8

HOPE IT HELPS