Question

two natural numbers differ by 3 and their product is 504 find the number​

Answer 1

let the numbers be x and y

x-y=3

x=3+y

xy=504

(3+y)y=504

y^2+3y=504

y^2+3y-504

y^2+24y-21y-504

y(y+24) -21(y+24)

y=21

x-21=3

x=3+21

x=24

Answer 2

Answer:

x=21 and (x+3)=24

Hope it helps!!