Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocal is 7/10.
Convert it to equation
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let two natural numbers are x and y
by first given condition
x-y=3
by second given condition
1/x+1/y=7/10
by first given condition
x-y=3
by second given condition
1/x+1/y=7/10
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