two natural numbers differ by 3.find the numbes if the sum of their resiprocal is 7/10
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let two number be x and y
x-y=3 equation1
1/x+1/y=7/10 equation2
but y=x+3
substitute in equation2
we get 7x^2+x+30
solving the quadratic equation
x=2 or -15/7
when x=2
then y=5
when x=-15/7
then y=6/7
therefore
x=2 y=5
mark me brainliest plz
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