two natural numbers differ by 4 and their product is 60, then the quadratic equation is
Answers
Answered by
0
Step-by-step explanation:
Let x be the larger number and y be the smaller, then x y = 60 and x-y = 4. Thus, x (x-4)= 60, or x^2–4x-60=
0.
hope its help you
Similar questions