Question

Two natural numbers differ by 6 and their sum is 36 , find the larger number ..... plz give Full explaination and easy explaination​

Answer 1

Question -:

Two natural numbers differ by 6 and their sum is 36. Find the larger number.

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The larger number = 21.

The smaller number = 15.

$\sf\underline{Solution }\dag$

Given -:

Difference between the numbers = 6.

Sum of the numbers = 36.

To find -:

The larger number.

Step-by-step process -:

Let the larger number be x.

Then the smaller number = x - 6.

Their sum is 36.

So,

$x + (x - 6) = 36$

$x + x - 6 = 36$

$2x - 6 = 36$

$2x = 36 + 6$

$2x = 42$

$x = \frac{42}{2}$

$x = 21.$

Therefore, the larger number is 21.

And the smaller number = x - 6.

Since x = 21, therefore the smaller number = 21 - 6 = 15.

Verification -:

To verify your answer, just see if the numbers differ by 6 and if their sum is 36.

Given -:

The larger number = 21.

The smaller number = 15.

15 + 6 = 21. So they differ by 6.

Now, we see if their sum is 36.

So, 21 + 15 = 36.

Since their sum is 36,

Hence verified ✔️✔️

Hope it helps! :)

Answer 2

Answer:21

Step-by-step explanation:

Since, Difference between tep numbers = 6, and their sum = 36Therefore, First natural number be x, and second number be x-6Therefore, x+x-6=36

=>2x=36-6 = 42

=>x = 42/2 = 21

Larger number is 21

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