Question

two neighbors work in the same factory for the different posts, so their salaries are also different. if the salary of one individual is 50% more than other ten by what percent others salary is of first salary

Answer 1

Step-by-step explanation:

Let salary of 2nd neighbour be x

" " 1st. " be x + 50%

ATQ,

$x = x + \frac{50}{100}$

$x = \frac{100x + 50}{100}$

$100x = 100x + 50$

$200x = 50$

$x = \frac{50}{200} = \frac{1}{4}$

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Answer 2

Percentage

Given:

Salary of one individual is 50% more than the other individual.

To find:

Percentage by which the salary of first people is greater than the other.

Explanation:

• First find the difference or the latest salary.
• Put them in formula for percentage.
• Find the required percentage with respect to the 1st given number.

Let the salary of 1st person be x.

Then the salary of the 2nd person will be $x+(50\% \ of\ x)$

So, the salary of 2nd person will be $1.5x$.

For finding percentage,

$\frac{{others\hspace{1}\hspace{1}salary}\times 100}{first\hspace{1}salary}$

$\frac{(1.5)x\times100} {x}$

$=150\%$

Hence, 2nd person salary is 150% of 1st salary.