two nicol prism are adjusted in crossed position .one of the nicol prism is then rotated through a 30 degree .calculate percentage of incident unpolarised light that will pass through the system of two nicol prism.
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Answer:I
I
2
=
8
3
=37.5 % (Rqed)
Explanation:The final arrangement of prism is as follows :-
transmitted intensity in I
2
.
unpolarized right of intensity I becomes half after crossing A
⇒I
1
=I/2
and as I
1
passes B, it follows mauns law:-
I
2
=I
1
cos
2
θ(θ=30
∘
)
⇒I
2
=
2
I
cos
2
(30
∘
)=
8
3I
⇒
I
I
2
=
8
3
=37.5 % (Rqed)
solution
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