Two no. are in ratio 5:3 if they differ by 18 what are the no.?
Answers
Answered by
13
Hi,
Here is your answer !
____________________________
Given that,
Two numbers are in the ratio 5 : 3
Let the numbers are 5k and 3k
Also given that,
Numbers are differ by 18
→ 5k - 3k = 18
→ 2k = 18
→ k = 9
Therefore Numbers are
5k = 5 × 9 = 45
3k = 3 × 9 = 27
Hence,
The required numbers are 45 and 27
Here is your answer !
____________________________
Given that,
Two numbers are in the ratio 5 : 3
Let the numbers are 5k and 3k
Also given that,
Numbers are differ by 18
→ 5k - 3k = 18
→ 2k = 18
→ k = 9
Therefore Numbers are
5k = 5 × 9 = 45
3k = 3 × 9 = 27
Hence,
The required numbers are 45 and 27
Answered by
8
Hii...☺
Here is your answer.....☺
================================
➡ Let the ratios be "x"
Therefore, the numbers are 5x and 3x.
Now, According to question we have,
➡ 5x - 3x = 18
➡ 2x = 18
➡ x = 18/2
➡ x = 9
=================================
Hence, numbers are:
5x = 5 × 9 = 45
and,
3x = 3 × 9 = 27
==================================
Two numbers are 45 and 27.
==================================
Thanks...☺
Here is your answer.....☺
================================
➡ Let the ratios be "x"
Therefore, the numbers are 5x and 3x.
Now, According to question we have,
➡ 5x - 3x = 18
➡ 2x = 18
➡ x = 18/2
➡ x = 9
=================================
Hence, numbers are:
5x = 5 × 9 = 45
and,
3x = 3 × 9 = 27
==================================
Two numbers are 45 and 27.
==================================
Thanks...☺
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