Two no. Are in the ratio 5:6 If 8 is subtracted from each the ratio become4:5find the number
Answers
Answered by
3
let the original nos.be 5x and 4x
A/Q-
(5x-8) / (6x-8)=4÷5
25x-40=24x-32
25x-24x=40-32
x=8
therefore,5x=40
6x=48
A/Q-
(5x-8) / (6x-8)=4÷5
25x-40=24x-32
25x-24x=40-32
x=8
therefore,5x=40
6x=48
Answered by
1
Let the two numbers be x and y.
Then by first condition,ratio of these two numbers is 5:6.
x:y = 5:6
x/y = 5/6
y = 6x/5 ........(1)
By second condition , then 8 is subtracted from each of the numbers,then ratio becomes 4:5.
x-8/y-8 = 4/5
5x-40 =4y-32
5x-4y = 8 ..........(2)
Now put the value of y in eq(2),we get,
5x-4(6x/5) = 8
25x-24x = 40
x = 40
Put the value of x in eq(2),we get,
y = 6/5 × 40
= 48
The required numbers are 40 and 48.
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