Question

two no diff by 40 when each differ by 8 bigger no becomes thrice the lesser no find the no​

Answer 1

Answer:

let first be x and second 40+y let y be bigger

atq

x-8 and y-8

y-8=3(x-8)

y-8=3x-24

3x-y=16

on solving the 2 equation

we get

x=-12

y=28

hope this help

Answer 2

Step-by-step explanation:

Let, Bigger number= x

Smaller number = y

By first condition

x-y=40----(1)

By second condition

y-8=3 (x-8)

y-8=3x-24

y-3x = -24+6

y-3x= -18

3x-y = -18----(2)

Now,

Subtract eqn 1 from 2

3x-y= -18

- x-y= 40

----------------

2x = -58

x = -58/2

x = -29

put x= -29 in eqn (1)

we get y = -69