Question

two no differ by 3 and their product is 504 . find the no

Answer 1

HELLO DEAR,

let the no. be x and another no. Will be (x+3)

and the product of no. be 504

x×(x+3) =504

=> x²+3x=504

=> x²+3x-504=0

= x²+ 24x - 21x - 504=0

=> x(x+24) -21(x+24)=0

=> (x-21)(x+24)=0

=> x=21 or x=-24





I HOPE ITS HELP YOU DEAR,
THANKS