Question

Two no. differ by 3. The sum of twice the smaller no. and thrice the greater no. is 19 . find the number​

Answer 1

Answer:

Step-by-step explanation:

let the two numbers be x and y such that x> y. so equation 1 is x-y = 3. so x = y + 3. equation 2 will be 2y + 3x =

Answer 2

Step-by-step explanation:

let the two no be x and y. our first equation will be x-y=3 means x=3+y second equation will be 2x+3y=19

2(3+y)+3y=19

6+2y+3y=19

5y=19-6

y=13/5

y=2.6

Now we got y but we have to find x so we will put y in this equation=x-y=3

x=3+2.6

x=5.6

y=2.6

x=5.6

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